write an equation in standard form of the line that passes through (7, -3) and has a y intercept of 2

Step-by-step explanation:

I would start with the form

y = mx + b

and then convert to standard form.  Using the given point and the given y-intercept, find the slope from

-3 = 7m + 2 ⇒ m = -5/7

y = (-5/7)x + 2  

7y = - 5x + 14

5x + 7y = 14 (standard form)

part a: 1.08

part b: 27.59

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.