What value is added to both sides of the equation x^2 − 6x = 10 in order to solve by completing the square? (1 point) Group of answer choices

−3

3

6

9

9

Step-by-step explanation:

use half the x coefficent and square it

x^2 − 6x + (-3)^2 = 10 + (-3)^2

x^2 - 6x + 9 = 10 + 9

(x - 3)^2 = 19

were is the equation

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50