I NEED A ANSWER SOON PLEASE!!! What is the area of a rectangle with vertices at (−4, 0), (−3, 1) , (0, −2), and (−1, −3)?

don't round any side lengths plz

6

Step-by-step explanation:

If you plot all 4 points, you will see that they are given in clockwise order around the rectangle.

If you take (-3, 1) and find the distance to (-4, 0), and take again (-3, 1) and find the distance to (0, -2), you will have the lengths of two consecutive sides. These sides can then be used as length and width to find the area.

distance from (-3, 1) to (-4, 0):

d = √[(-3 - (-4))² + (1 - 0)²] = √[1² + 1²] = √2

distance from (-3, 1) to (0, -2):

d = √[(-3 - 0)² + (1 - (-2))²] = √[(-3)² + 3²] = 3√2

area = LW = √2 × 3√2 = 3 × 2 = 6

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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