The number of accidents that a person has in a given year is a Poisson random variable with mean $. However, suppose that the value of $ changes from person to person, being equal to 3 for 75 percent of the population and 4 for the other 25 percent. If a person is chosen at random, what is the probability that he will have (a) 0 accidents and (b) exactly 4 accidents in a certain year? What is the conditional probability that he will have 4 accidents in a given year, given that he had no accidents the preceding year?

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square

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step-by-step explanation: hi!

113.42

i hope that is right.

step-by-step explanation: