(y+3):(y+5)=k:1 show that y=5k-3/1-k

  y = (5k -3)/(1 -k)

Step-by-step explanation:

  (y +3)/(y +5) = k/1

  y +3 = k(y +5) . . . . . multiply by (y+5)

  y +3 = ky +5k . . . . . eliminate parentheses

  y -ky = 5k -3 . . . . . . subtract (ky+3)

  y(1 -k) = 5k -3 . . . . . factor out y

  y = (5k -3)/(1 -k) . . . . divide by the coefficient of y

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Additional comment

When this is written in plain text, as above, the parentheses are essential grouping symbols for the numerator and denominator. If the equation is typeset:

then no parentheses are required, because the fraction bar serves to identify the numerator and denominator expressions.

When written without parentheses,

  y = 5k -3/1 -k = 5k -(3/1) -k = 4k -3 . . . . not the same as above

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.