Challenge. The price of Stock A at 9 A. M. was $13.66. Since then, the price has been increasing at the rate of $0.05 each hour. At noon the price of Stock B was $14.16. It begins to decrease at the rate of $0.15 each hour. If the two rates continue, in how many hours will the prices of the two stocks be the same?

7/4

Step-by-step explanation:

We can write equations for increasing stock and decreasing stock and find our answer.

Let number of hours be "h" for both to be same

For first, we can write:

13.66 + 0.05h

But, second one starts from noon, so already 12pm - 9am = 3 hours gone, so stock A increased by 3 x 0.05 = 0.15, so we equation would be:  

13.81 + 0.05h

Now, Stock B's equation [from noon]:

14.16 - 0.15h

Equate and solve:

so we will do 13.81 + 0.05h = 14.16 - 0.15h

number with number

variables with variables

0.2h   = 0.35

divide 0.2 both sides

answer is

1.75 or if its in fraction form 7/4

1.75 hours

Step-by-step explanation:

(13.66 +3*0.05) + (0.05 * h) = 14.16 - (0.15 * h)

13.81 + 0.05h = 14.16 - 0.15h

0.05h + 0.15h = 14.16 - 13.81

0.20h = 0.35

h = 0.35/ 0.20

h = 7/4

i can you with this question sweetie!

step-by-step explanation: