The length of a rectangular garden is 17 feet longer than its width. If the area of the garden is 308 square feet, what are the dimensions of the garden? A) First, write a quadratic equation in the from
aw^2+bw+c=0
you can solve to answer the question given. Let w be the width of the garden.

Use the variable w

B) Factor your equation from part [a] into the form

The factored equation is

C)Use your factored equation to find the length and width of the
feet.

  A) w^2 +17w -308 = 0

  B) (w -11)(w +28) = 0

  C) length: 28 ft; width: 11 ft.

Step-by-step explanation:

If w is used to represent the width of the garden, then its length is w+17, and the relation to area is ...

  w(w +17) = 308

  w^2 +17w -308 = 0 . . . . the desired quadratic equation

__

The equation can be factored as ...

  (w -11)(w +28) = 0 . . . . . the factored equation

__

The positive solution for w in the factored equation is w = 11. Then the length of the garden is ...

  w +17 = 11 +17 = 28

The length and width of the garden are 28 feet and 11 feet, respectively.

step-by-step explanation:

hmu if ur willing to do a algebra a online class i’ll pay 600 hmu on the gram profitpreme