Find the horizontal and vertical asymptotes of the graph of the function f(x) = 2x^2+1/3x-5

HA= None VA= 5/3

Step-by-step explanation:

The HA is none because the bottom part is missing x squared so you add x squared and it will be 2/0 which means it's not possible which means HA= none. VA is 5/3 because you set the denominator to 0 so you add 5 then divide by 3 so the answer for VA is 5/3

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47