The length of a rectangle is 6 yd longer than its width. If the perimeter of the rectangle is 68 yd, find its length and width.

Length = 20, width = 14

Step-by-step explanation:

Let  L  represent length.

Let W  represent width.

Since the length is 6 yd longer than its width:  L  =  6 + W

The formula for perimeter:  P  =  2L + 2W    

Since the perimeter is 68 yds:     68 =  2L + 2W

Substituting:                             68  =  2(6 + W) + 2W

                                               68  =  12 + 2W + 2W

                                              68  =  12 + 4W  

                                               32  =  4W

                                                W  =  8 yds

Since  L  =  6 + W  --->  L  =  14 yds

Length = 20, width = 14

Step-by-step explanation:

Let width be w, and length be w + 6.

Perimeter of a rectangle = 2l + 2w

                                  68  = 2(w + 6) + 2w

                                  68  = 2w + 12 + 2w

                                  68  = 4w + 12    [subtract 12 from both side]

                                  56  = 4w            [Divide 4 from both side]

                                   w   = 14

Plug w in l, where l = w + 6 = 14 + 6 = 20

step-by-step explanation:

step-by-step explanation:

consider the parallelogram shown in the attached image.

in the parallelogram hijk, the length of hk is given as,

from the properties of parallelogram we know that the opposite sides of a parallelogram are parallel to each other and are equal in measure.

therefore, the length of the side ij must be equal to the length of the side hk and that is .

hence, the expression for the length of ij confirms that hijk is a parallelogram.