In the given figure find the area of the parallelogram ABCD.

Given info:- In a Parallelogram ABCD , BC = 48 cm ,

AB = 25 cm and AE = 7 cm. And here we have to find the area of the given Parallelogram ABCD?

Explanation:-

In a Parallelogram ABCD ,

And

∆ AEB is a right angled triangle

Right angle at E

AB is the hypotenuse

We know that

By, Pythagoras theorem

Hypotenuse² = Side² + Side²

⇛ AB² = AE²+ BE²

⇛ 25² = 7² + BE²

⇛ 625 = 49 + BE²

⇛ BE² = 625-49

⇛ BE² = 576

⇛ BE = ±√576

⇛ BE = ±24

Since the length of the side cannot be negative

⇛ BE = 24 cm

⇛ BC = AD

⇛ AD = 48 cm

⇛ AE + ED = 48 cm

⇛ 7+ED = 48 cm

⇛ ED = 48-7

⇛ ED = 41 cm

We know that

Area of a Parallelogram = bh sq.units

Area of the given Parallelogram ABCD

⇛ AD × BE or BC × AE

⇛ 48 × 24 sq.cm

⇛ 1152 sq.cm

Therefore, the area of the given Parallelogram ABCD is 1152 sq.cm

Additional comment:

Each side of the parallelogram is called its base.

Opposite sides are equal and parallel in a Parallelogram.

If you have any doubt, then you can ask me in the comments.

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