The temperature in the production department is 21°C at 12 noon. If the temperature increases 1.5° C every hour, what will the temperature
be at 5 pm?

28.5 (I don't know if this is fully correct)

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol