Find the equation of the line perpendicular to and passing through the point (−6; 1).

⦿ Hi There! ⦿

Point-Slope form:

y-y1=m(x-x1)

y-1=m(x-(-6)

Perpendicular lines have slopes that are opposite reciprocals.

It means that if we have -1/2, we flop it over and make it positive.

So the slope of the new line is 2.

y-y1=m(x-x1)

y-1=2(x-(-6)

y-1=2(x+6)

y=1=2x+12

y=2x+12-1

y=2x+11

Hope it helps!

~Just a cheerful gal

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