Question Write an equation in slope-intercept form of the line that passes through (6, −1) and (3, −7). Please help

Step-by-step explanation:

(x1,y1) = (6,-1)

(x2,y2) = (3,-7)

(y - y1)/(y2 - y1) = (x - x1)/(x2 - x1)

(y + 1)/(-7 + 1) = (x - 6)/(3 - 6)

(y + 1)/-6 = (x - 6)/-3

(y + 1)/2 = (x - 6)/1

y + 1 = 2(x - 6)

y = 2x - 12 - 1

y = 2x - 13

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

is only a line? i think so