The cost of admission to a festival was $112 for 9 children and 3 adults. The admission was $108 for 8 children and 3 adults in another festival. How much was the admission for each child and adult?

cost of admission for each child was $4.00, and each adult was $25.33

Step-by-step explanation:

When solving questions like these , I like to break down the problem so I understand it better.

Let x ---> cost of the admission for each child

Y > cost of the admission for each adult

9x+3y = 112 ---> equation A

8x + 3y = 108 ---> equation B

Subtract B from A

9x+3y=112

-8x+3y = 108

x = 112-108

x = 4

Find value of y by substituting value of x into equation

9(4)+3y=112

Solve for y

36+3y = 112

3y = 112=36

3y = 76

y = 25.33

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐