A student has some $1 and $5 bills in his wallet. He has a total of 13 bills that are worth $41. How many of each type of bill does he have?

There are  6  one dollar bills and  7  five dollar bills.

Step-by-step explanation:

Let the number of $1 bills be  x  and the number of $5 bills be  y .

x + y = 13

x + 5 y = 41

Solve using substitution:

y = 13 -x

 x + 5 ( 13 − x ) = 41

x + 65 − 5 x = 41

− 4 x =41 − 65

− 4 x =− 24

x = 6

x + y = 13

6 + y = 13

y = 7

Hence, there are  6  one dollar bills and  7  five dollar bills.

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step-by-step explanation: