What is the perimeter (distance around) triangle ABC with vertices at the following
coordinates:
(3,5), (1.-4) , (-3.1)
(Hint: find the distance of each side individually!

2xy/9 is the answer to this problem

So the first thing we do is to multiply the top equation by 3. the reason i want to do this is i notice there will be a 6y on both equations and can possibly add/subtract them. so we get 6y = -3x + 27. adding that and the second equation we get 6x = 27-15 which is 12. divide by 6 and we get 2. ∴ x = 2. substituting 2 into the first equation we get 2y = -2 + 9 which is 7. divide by 2 and we get 7/2. ∴ y = 7/2, x = 2.