The Katz family went to the Central Park Zoo. There they saw twice as many monkeys as seals. The number of bears was 1 less than the number of monkeys. There were 3 times as many giraffes as bears. There are 40 animals in the zoo. How many of each animal did the Katzes see?

4 seals 8 monkeys 7 bears 21 giraffes

Step-by-step explanation:

4 seals 4 x 2 is 8

8-1 is 7

7x3 is 21

21+7=28

4+8 is 12

28+12 is 40

4 seals

8 monkeys

7 bears

21 giraffes

Step-by-step explanation:

x = Number of seals

2x = Number of monkeys

2x - 1 = Number of bears

3(2x - 1) = Number of Giraffes

Total: 40 animals

We can solve this by simple algebra. Once we find x, we can fit this into our 4 equations to find out each animal did the Katzes see. Below is the explanation.

x = Number of seals

x + 2x + 2x - 1 + (3 x 2x - 1) = 40

5x - 1 + 3(2x - 1) = 40

5x - 1 + 6x - 3 = 40

11x - 4 = 40

11x = 44

x = 4

Lets return to our equations. We will then replace x with the number obtained.

x = 4 seals

2(4) = 8 monkeys

2(4) - 1 = 7 bears

3(2{4} - 1) = 21 Giraffes

Total: 40 animals

And that solves the problem. Hope this helps and if possible, brainliest please?