There are 130 people in a sport centre. 61 people use the gym.
68 people use the swimming pool.
60 people use the track.
25 people use the gym and the pool.
30 people use the pool and the track.
19 people use the gym and the track.
6 people use all three facilities.
A person is selected at random.
What is the probability that this person doesn't use any facility?

59 over 130

Step-by-step explanation:

As shown in the Venn diagram,

Let

U=[The total number of people in the sport center ]

This implies that

n(U)=130

G=[Those who use the gym]

This implies that

n(G)=61

P=[Those who use the pool]

This implies that

n(P)=68

T=[Those who use the track]

This implies that

n(T)=60

a=those who use only the gym

b=those who use only the pool

c=those who use only the track

From the digram,

a=61-(13+6+19)=61-38=23

b=68-(6+24+19)=68-49=19

c=60-(13+6+24)=60-43=17

The number of people who use exactly one facilities=a+b+c=23+19+17=59

Hence, the probability that a person selected at random uses exactly one the facilities

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !

idk

step-by-step explanation: i just don't