Does anybody know the answer to this question f(x)=x^3-x^2-10x-8

(X+1) (x - 4) (x+2)

Step-by-step explanation:

All the coefficients are integers so apply the rational zeros theorem.

The coefficient of x^3 is 1.

Divide (x^3-x2-10x-8)(x+1) = x^2-2x-8 with remainder = 0

The remainder is 0. (x+1) is a factor.

(x + 1) ( x^2 - 2x - 8)

x^2 - 2x - 8 (-4 * 2= 8) and -4 + 2 = -2)

= (x -4) (x+2)