In ΔJKL, \overline{JL} JL
is extended through point L to point M, \text{m}\angle JKL = (3x-16)^{\circ}m∠JKL=(3x−16)
∘
, \text{m}\angle LJK = (2x+15)^{\circ}m∠LJK=(2x+15)
∘
, and \text{m}\angle KLM = (8x-19)^{\circ}m∠KLM=(8x−19)
∘
. Find \text{m}\angle LJK. m∠LJK.

the correct answer is 5 6 and 7

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204