A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 100 m long and 60 m wide. Find the area of the training field. Use the value 3.14 for , and do not round your answer. Be sure to include the correct unit in your answer.

Step-by-step explanation:

given,

length = 100 m

breadth = 60 m

we know,

area = l × b

now,

100 × 60 = 6000 m

therefore, area of rectangular field is 6,000 m.

and for both the semicircle if we add both the semicircle we will get a complete circle.

as the width of the rectangle is the diameter of circle so the radius of the circle is 60/2 = 30m

we know,

Area = πr²

now,

→ 3.14 × 30²

→ 3.14 × 900

→ 2826 m

so,

area of rectangle + area of circle = area of the training field.

→ 6000 + 2826 = 8826.

therefore, area of training field is 8,826 m.

hope this answer helps you dear...take care and may u have a great day ahead!

8826 m²

Step-by-step explanation:

The field is composed of a rectangle and a circle .( the 2 semicircles form a complete circle when placed together )

area = area of rectangle + area of circle

        = lb + πr² ( r = 60 ÷ 2 = 30 )

        = (100 × 60) + (3.14 × 30²)

        = 6000 + (3.14 × 900)

        = 6000 + 2826

        = 8826 m²

the red lines denote the population of the bacteria after 35 hours. that would be 2,409.24. the y-intercept is the blue line which is 800 because that is the starting point. the equation used to make the graph is 800(1.032)^h, where h is the number of hours.

step-by-step explanation:

c

step-by-step explanation: