Suppose y varies directly as x, and y=14 when x=4. What is the value of y when x=9

Given :-

y varies directly as x, and y=14 when x=4.

To Find :-

the value of y when x=9 .

Solution :-

According to Question ,

y = kx ( k is constant )

When y = 14 and x = 4 ,

14 = k(4)k = 14/4k = 7/2

When x = 9 ,

y = 7/2*9 y = 63/2y = 31.5

69 i think because is the only one square

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph

there is a hike in both the graphs so the graphs are increasing on their domain.x-intercept of log x and log 6x are differentthere is a vertical asymptote of both the graphs so there is no y-interceptas both the graphs are increasing so there is no horizontal asymptote