Mateo jogs for 3 3/4 miles on Saturday and 4 2/5 miles on Sunday. What is the total distance, in miles, that Mateo jogged in the past 2 days?

Mateo jogged 8 3/20 miles in the past 2 days.

Step-by-step explanation:

Given:-

Distance on Saturday = 3 3/4

Distance on Sunday = 4 2/5

Total distance = 3 3/4 + 4 2/5

                       = 15/4 + 22/5

                       = LCM of deniminators (20)

                       = 75/20 + 88/20

                       = (75 + 88)/20

                      =  163/20

                      = 8 3/20

8+ (3/20)

Step-by-step explanation: We will assume that "today" is a Monday.

3+(3/4) + 4+(2/5)

7 + (3/4) + (2/5)

7 + (3/4)*(5/5) + (2/5)*(4/4)

7 + (15/20) + (8/20)

7 + (23/20)

8+ (3/20)

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

98 points djdjsi zisksis sjsjsi sisksj sksjdj sksks sjsisj