Please answer the question below and show working out pls p. s. the answer is $28.14

9514 1404 393

  $28.14

Step-by-step explanation:

The area of a container will be the sum of the base area and the lateral area. The relevant formulas are ...

  A = πr^2 . . . . . . . . area of the circular base with radius r

  A = 2πrh . . . . . . .  area of the side of the container

The sum of the two areas is ...

  Atot = πr^2 +2πrh = πr(r +2h) = π(7/2 cm)(7/2 cm +2·21 cm) = (π/4)(7)(91) cm^2

  Atot = 159.25π cm^2 = 0.015925π m^2 . . . . metal area per container

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Then 125 containers will have an area of ...

  Aall = (125)(0.015925π m^2) = 1.990625π m^2 ≈ 6.25373 m^2

The price of this amount of sheet metal will be ...

  (6.25373 m^2)($4.50 /m^2) = $28.14 . . . cost of 125 containers

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Additional comment

1 cm = 0.01 m, so (1 cm)^2 = (0.01 m)^2 = 0.0001 m^2

answer is : muchas/tipicas

have a nice day!

~recklesschicken

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°