Find three consecutive integers such that the product of the first two is 10 less than the product of the last two.

4

5

6

Step-by-step explanation:

Since we don't know the three consecutive numbers, let's call them x,x+1,and x+2.

Product of first two means x(x+1)=x^2+x

Product of last two means

(x+1)(x+2)=x^2+2x+1x+2=x^2+3x+2

"product of the first two is 10 less than the product of the last two"

So we have the equation x^2+x=x^2+3x+2-10

Simplify on right side: x^2+x=x^2+3x-8

Subtract x^2 on both sides: x=3x-8

Subtract 3x on both sides: -2x=-8

Divide both sides by -2: x=4

x=4

x+1=4+1=5

x+2=4+2=6

Check:

The product of first two is 10 less than the product of last two.

4(5)=20

5(6)=30

It's true that 30-10=20.

the correct answer is a) "catholic church".

the proposals that liberals in mexico made during 1855 were particularly focused on a person's individual rights, such as the freedom of speech, the freedom of conscience, freedom of assembly, and the right to possess weapons.

when the constitution was formally published 2 years later (1857). it also contained an article which permitted education free from any religious influence, the removal of the catholic church institutional privileges, and the sale of property belonging to the church. all of these provisions were clearly against the catholic church interests.