Urgent Write the equation of a line that is parallel to the line 2x +3y = 5 and contains the point (2, -1)

2x+3y= -1

Step-by-step explanation:

2x+3y=5

3y= -2x+5

y= -2/3x + 5/3

m= -2/3

put the points( -2,1) in this equation to get b

1= -2(-2/3)+b

b= 1-4/3

=-1/3

so the equation is

y = -2/3x -1/3

3y= - 2x-1

2x+3y= -1

d is correct

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2