Which sequence of transformations will certainly work to take triangle XYZ to triangle STU? A

Translate XYZ by the directed line segment XB. Rotate X'Y'Z' using B as the center by angle Y'AB. Reflect X''Y''Z'' over AB.

B

Translate XYZ by the directed line segment XA. Rotate X'Y'Z' using A as the center by angle Y'AB. Reflect X''Y''Z'' over AB.

C

Rotate XYZ using X until XY is lines with ST and then reflect over a line halfway between X'Y'Z' and ABC

D

Translate XYZ by the directed line segment XA. Translate X'Y'Z' by the directed line segment Y'T. Translate X''H''J'' by the directed line segment J''T.

12m

step-by-step explanation:

square root means have of a number so have of 3 is 1.5 then multiply it by 8 and you get your answer!

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5

you divide them and then you get the answer i took this class this year

step-by-step explanation: