The price of Stock A at 9 A. M. was $13.58. Since then, the price has been increasing at the rate of $0.09 each hour. At noon the price of Stock B was $14.08. It begins to decrease at the rate of $0.15 each hour. If the two rates continue, in how many hours will the prices of the two stocks be the same?

2 2/15 hours from noon the stock prices will be same.

Step-by-step explanation:

We can write equations for increasing stock and decreasing stock and find our answer.

Let number of hours be "t" for both to be same

For first, we can write:

13.14 + 0.06t

But, 2nd one starts from noon, so already 12pm - 9am = 3 hours gone, so stock A increased by 3 * 0.06 = 0.18, so we equation would be:

13.32 + 0.06t

Now, Stock B's equation [from noon]:

13.64 - 0.09t

Equate and solve:

\begin{gathered}13.32 + 0.06t=13.64-0.09t\\0.15t=0.32\\t=2\frac{2}{15}\end{gathered}13.32+0.06t=13.64−0.09t0.15t=0.32t=2152

In 2  2/15 hours, the prices will be same

answer: idk

step-by-step explanation:

the answer is "add 2y and y"

step-by-step explanation:

you need to collect the like terms first.