Brahmagupta's solution to a quadratic equation of the form ax? + bx = c involved only one solution. Which solution would he have found for the equation 3x2 + 4x = 6?
O x =
4(3)(6) + 42 - 4 - 2722-4 - V22 - 2
2 (3)
6
3
O x = 4(3)(4)
+62 - 6
2(3)
2/21-6-21-3
3
6
O x = 4(4)(6) + 32 - 3
2(4)
105 - 3
8
O x = 4(3)(6) – 42 +4 - 2/14+4
14 + 2
3
2 (3)
6

9.

step-by-step explanation:

if you want to separate 54 into 6 individual tiers then you need to divide if you want to separate 54 into 6 individual tiers then you need to divide 6 and 54.

you will get 9.

if you divide 9 by 6 you will get 54.

- hope i .

1.   an exact solution requires a radical solution - no decimal approximation.2. (a)4x^3 = 756x^3 = 756/4 = 189x =   cube root of 189 =   5.74   to nearest hundredth answer(b)   189 = 3*3*3*7   so we can write the cube root of 189 as 3∛7 answerchecking (a) 4*(5.74^3 =   756.48   which is very close(b)   4* ((3∛3)^3   = 4*189   = 756   - spot on! 3. i would use solution b because the original question asked for an exact solution.