If a polynomial function f(x) has roots -6 square root of -3, what must be a factor of f(x) 1. (x-/3)
2. (x-6)
3. (x-(-/3+6))
4. (x+(-/3+6)

PLEAS

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

the answer is -1 for this question

step-by-step explanation:

the answer is z7+8/5