Find the area of right triangle def, round to nearest tenth if necessary D(-6,-1),E(1,-3),F(3,4) HELP

Step-by-step explanation:

Two of the legs will be at right angles to each other and have negative reciprocal slopes. Area will be half of the product of these two legs.

slope of DE (-3 - (-1)) / (1 - (-6)) = -2/7

slope of EF (4 - (-3)) / (3 - 1) = 7/2

so these two are perpendicular

check the DF line to be certain

slope of DF (4 - (-1)) / (3 - (-6)) = 5/9

Length of DE =  √(-2² + 7²) = √53

Length of EF = √(7² + 2²) = √53

Area of triangle

A = ½√53√53 = 26.5 units²

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

(-5,-28)

i graphed to on desmos.