IF 0 ≤theta°≤360°

find cos(2theta-10°)=-1/2

θ

can be in the first quadrant

0

≤

θ

≤

90

or the fourth quadrant

270

≤

θ

≤

360

If

θ

is in the first quadrant,

then

sin

θ

=

5

13

cos

θ

=

12

13

tan

θ

=

5

12

Therefore,

sin

2

θ

=

2

sin

θ

cos

θ

=

2

×

5

13

×

12

13

=

120

169

cos

2

θ

=

cos

2

θ

−

sin

2

θ

=

(

12

13

)

2

−

(

5

13

)

2

=

144

169

−

25

169

=

119

169

If

θ

is in the fourth quadrant,

then

sin

θ

=

−

5

13

cos

θ

=

12

13

tan

θ

=

−

5

12

Therefore,

sin

2

θ

=

2

sin

θ

cos

θ

=

2

×

−

5

13

×

12

13

=

−

120

169

cos

2

θ

=

cos

2

θ

−

sin

2

θ

=

(

12

13

)

2

−

(

−

5

13

)

2

=

144

169

−

25

169

=

119

169

d. millimeters per hour.

step-by-step explanation:

we are given that,

carlo used a rain gauge to measure the amount of water his lawn is receiving from the sprinklers.

since, according to the options, we see that,

water cannot be measured by 'miles per hour', 'meters per second' and 'grams per seconds'.

we get that, the water can be measured by 'millimeters per hour'.

hence, the appropriate rate for describing the amount of water is 'millimeters per hour'.

the answer is stop cheating on things stoopid

step-by-step explanation:

im eatin up the 44