A store received 620 containers of milk to be sold by March 1. Each container cost the store $0.78 and sold for $1.56. The store signed a contract with the distributor in
which the distributor agreed to a $0.40 refund for every container not sold by March
1. If 430 containers were sold by March 1, how much profit did the store make?

9514 1404 393

  $263.20

Step-by-step explanation:

The number not sold was ...

  620 -430 = 190

The cost for a container not sold was ...

  $0.78 -0.40 = $0.38

__

The cost of containers sold was ...

  $0.78 × 430 = $335.40

The cost of containers not sold was ...

  $0.38 × 190 = $72.20

The total cost for the 620 containers of milk was ...

  $335.40 +72.20 = $407.60

The total revenue from the 430 containers sold was ...

  $1.56 × 430 = $670.80

Then the profit was ...

  profit = revenue - cost

  profit = $670.80 -407.60 = $263.20

Additional comment

The calculation can be simplified to ...

  $1.16 × (number sold) - $0.38 × (number bought)

y=−9/2x+10

step-by-step explanation:

let's solve for y.

0−9x−2y=−20

step 1: add 9x to both sides.

−9x−2y+9x=−20+9x

−2y=9x−20

step 2: divide both sides by -2.

−2y

−2

=

9x−20

−2

y=

−9

2

x+10

nswer: a   y-axis

step-by-step explanation: