WHAT IS THE DOMAIN OF THE FUNCTION fx=(x+1)/(x^2 +2x-3)

Domain : R−{−1,3}

Range: R

Step-by-step explanation:

Equate the denominator(x2−2x−3) to zero, then solve the equation for x

→x2−2x−3=0

→x=−(−2)±√(−2)2−4⋅(1)⋅(−3)2⋅1

→x=1±2

⇒x=−1 and x=3

This means that, when x=−1 or 3, we have the x2−2x−3=0

Implying that f(x)=x0 which is undefined.

Hence, the domain is all real numbers except −1

and 3

Also written as Df=(−∞,−1)∪(−1,3)∪(3,+∞)

ian gone lie this got me confused

step-by-step explanation: