Mathematics, 09.10.2021 01:00 BARRION1981
Find the value of the given
function's derivative at x = 0.
f(x) = k(g(x))
g(x) = 2x - (x - 2)^2
k'(-4) = 25
f(0) = [?]
Answers: 2
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Find the value of the given
function's derivative at x = 0.
f(x) = k(g(x))
g(x) = 2x -...
f(x) = k(g(x))
g(x) = 2x -...
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