NEED QUICK ASSIGNMENT IS OVERDUE how many solutions do the following have? **NEED WORK SHOWN ON HOW TO SOLVE EACH ONE!!

6r + 7 = 13 + 7r
-14 + 6b + 7 – 2b = 1 + 5b
8x + 4(4x + 3) = 4(6x + 4) - 4

I gotchu :)

1) 6r + 7 = 13 + 7r    - Subtract 6r from both sides...

   7 = 13 + r       - Subtract 13 from both sides

 6(-6) + 7 = 13 + 7(-6)

  -36 + 7 = 13 -42

   -29 = -29  ( It works )

2) -14 + 6b + 7 - 2b = 1 + 5b    - Combine like terms...

   -7 + 4b = 1 + 5b        - Add 7 to both sides

    4b = 8 + 5b       - Subtract 5b from both sides

     -b = 8            - Divide both sides by -1

3) 8x + 4(4x+3) = 4(6x + 4) - 4     - Distributive property

   8x + 16x + 12 = 24x + 16 - 4        Combine like terms

   24x + 12 = 24x + 12       - Both terms equal each other

    0 = 0

Since both terms equal each other, all numbres fit.

it is b)

hope this : )

step-by-step explanation: