What is the equation of the line that passes through the point (5,−2) and has a slope of 6/5?

y = x - 8

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = , then

y = x + c ← is the partial equation

To find c substitute (5, - 2 ) into the partial equation

- 2 = 6 + c ⇒ c = - 2 - 6 = - 8

y = x - 8 ← equation of line

its d. the first coordintaes are 10,32

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2