The total length of two ships is 1841 feet. The difference in their lengths is 13 feet. Find the length of each ship.

9514 1404 393

  927 ft

  914 ft

Step-by-step explanation:

The lengths are half the sum plus or minus half the difference:

  1841/2 ± 13/2 = {1854/2, 1828/2} = {927, 914} . . . feet

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Let x represent the shorter length. Then x+13 is the longer length. Their total is ..

  x +(x +13) = 1841

  2x = 1841 -13

  x = (1841 -13)/2 . . . . half the sum minus half the difference

Then the longer length is ...

  x+13 = (1841/2) -(13/2) +13

  x +13 = (1841/2) +(13/2) . . . . half the sum plus half the difference

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3