11p-5=28 plz help i need help on this paper and i dont really get it

Step-by-step explanation:

Solve

1

Add  

5

5

5

to both sides of the equation

1

1

−

5

=

2

8

11p-5=28

11p−5=28

1

1

−

5

+

5

=

2

8

+

5

11p-5+{\color{#c92786}{5}}=28+{\color{#c92786}{5}}

11p−5+5=28+5

2

Simplify

Add the numbers

Add the numbers

1

1

=

3

3

11p=33

11p=33

3

Divide both sides of the equation by the same term

1

1

=

3

3

11p=33

11p=33

1

1

1

1

=

3

3

1

1

1111p=1133

4

Simplify

Cancel terms that are in both the numerator and denominator

Divide the numbers

=

3

p=3

p=3

Solution

=

3

so basically yeah p = 3

11p-5=28

Add 5 on both sides

11p=33

divide by 11 both sides

ANSWER IS

p=3

Step-by-step explanation:

ksksfksag;

2.14x - 12.18 = -5.76

add 12.18 to each side

2.14x -12.18 +12.18 = -5.76 +12.18

2.14 x =6.42

divide by 2.14

2.14x/2.14 = 6.42/2.14

x=3