Expand and simplify the following: -3(2x-1)^2 + 12x^2

Can someone please show me their working of this so I can get my head around it!

Hope that this is helpful.

Step-by-step explanation:

-3(2x-1)^2+12x^2

= -3[(2x-1)(2x-1)]+12x^2

=-3[2x(2x-1)-1(2x-1)]+12x^2

=-3(4x^2-2x-2x+1)+12x^2

=-3(4x^2-4x+1)+12x^2

=-12x^2+12x-3+12x^2

=(-12x^2+12x^2) +12x-3

=0+12x-3

=12x-3

proofs involving isosceles triangles often require special consideration because an isosceles triangle has several distinct properties that do not apply to normal triangles.(more about triangle types) therefore, when you are trying to prove that two triangles are congruent, and one or both triangles, are isosceles you have a few theorems that you can use to make your life easier.

step-by-step explanation:

an isosceles triangle has two congruent sides and two congruent angles. the congruent angles are called the base angles and the other angle is known as the vertex angle. ∠bac and ∠bca are the base angles of the triangle picture on the left. the vertex angle is ∠abc

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!