What is the median of the following string of values?
55, 18, 58, 49, 8, 77, 62, 26, 7.11

The answer is 49 if we are to assume you meant 7.11 and not 7,11.

If you meant 7,11 - the answer is 28.5.

Step-by-step explanation:

If we are assuming you meant "7,11" and not "7.11", then we would start by removing the lowest and highest numbers from the list respectively, and repeating the process until you only have 1 or 2 numbers left.

Here are the pairs of numbers removed if we are assuming you meant 7.11;

7.11 / 77

8 / 62

18 / 58

26 / 55

We are left with 49, and that would be your median.

However, if we were to assume you meant 7,11, then we'd have to start over and repeat the process.

7 / 77

8 / 62

11 / 58

18 / 55

26 / 49 is our final answer; however we are not to assume this as we need a definite number. To resolve this, we would need to average the two numbers. To do this, we add them together and divide by how many numbers we added.

26 + 49 = 75.

75 / 2 = 28.5

Your median for this would be 28.5.

Hope this helps! Have a great rest of your day. :)

answer: yes, since the line has a steeper rate of change than the exponential the y-values will be greater and they will only intersect one time.

this is the formula: v = the value of investment at the end of the time period

p = the principal amount (the initial amount invested)

r = the annual interest rate

n = the annual frequency of compounding (how many times a year interest is added)

t = the number of years the money is invested

^ means raise to the power of