Helen and Ivan had the same number of coins. Helen had a number of 50-cent coins, and 64 20-cent coins. These coins had a mass of 1.134kg. Ivan had a number of 50-cent coins and 104 20-cent coins.(a) Who has more money in coins and by how much?(b) given that each 50-cent coin is 2.7g more heavier than a 20-cent coin, what is the mass of Ivan's coins in kilograms?

Step-by-step explanation:

Let H stand for the total number of Helen's coins and I for the total number of Ivan's coins.

We are told that H = I

We also know that Helen has 64 20-cent coins.  The total mass of her coins, H, is 1.134kg.

Ivan has 104 20-cent coins.  

We are told that both have a non-defined number of 50-cent coins.

(a) Who has more money in coins and by how much?

Since both have an equal number of coins, but Ivan has more 20-cent coins than Helen, Helen must therefore have a greater number of 50-cent coins, making her the richest of the two.

Helen has (H - 64) 50-cent coins

I has (I - 104) 50-cent coins

Since H=I, the ratio of Helen's to Ivan's 50-cent coins is (H-64)/(H-104)

But it is here that I don't know how to calculate the total value of coins, without more information.  All I know is that both have a known number of 20-cent coins, but I don't see an upper limit to the number of 50-cent coins.

Let's assume both had 200 coins.  The breakdown is shown in the attachment.

Sorry, I may see the answer tomorrow, but I need to leave now.

if you use photomath right away it will give you the answer not like this app that you have to wait for people.