Let f be a real-valued function defined on [0,∞), with the properties: f is continuous on [0, ∞), f(0) = 0

f ..1 exists on (0, ∞), and f ..1

0 is monotone increasing on (0,∞).

Let g be the function given by: g(x) = f(x)

for x ∈ (0, ∞).

How do I prove that g is monotone increasing on (0,∞)?

im not sure this is right

g'(x) = 6b(-5x + 1)^5 (-5)

g'(x) = -30b(-5x +1)^5

g''(x) = -30b(5)(-5x + 1)^4 (-5)

g''(x) = 750b (-5x +1)^4

g(x) = b(−5x + 1)6 − a

when

g(-x) = b(5x +1)6 - a

g'(x) = -30b(-5x +1)^5 = 0

-5x +1 = 0

x = 15

answer: i'm great at algebra

~coco

step-by-step explanation:

here is the

mark brainliest pl