The equation for line j can be written as y = x + 7. Parallel to line j is line k, which passes through the point (-3, -1). What is the equation of line k?

Step-by-step explanation:

parallel lines have the same gradient..

y=x+7 has a gradient of 1.

If line J which is parallel to k has a gradient of 1 then they are the same.

gradient (m) =∆y

∆x

=y- -1 = 1

x - - 3

= y + 1

x+3

y+1=x+3

y=x +3 +1

y = x + 4(equation for k)

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

the answer is 8/21

hope this