A certain medical test is known to detect 55% of the people who are afflicted with the disease If 10 people with the disease are administered the test, what is the probability that the test will show that All 10 have the disease, rounded to four decimal places?
At least 8 have the disease, rounded to four decimal places?
At most 4 have the disease, rounded to four decimal places?

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

i have not got your picture clearly so see it once again