Write the equation of the line that passes through the points (
−
3
,
−
5
)
(−3,−5) and
(
3
,
1
)
(3,1). Put your answer in fully reduced point-slope form, unless it is a vertical or horizontal line.

y+2-x=0

Step-by-step explanation:

Here,

(-3,-5)=(x1,y1)

(3,1)=(x2,y2)

Slope(m)=y2-y1/x2-x1

=1-(-5)/3-(-3)

=1+5/3+3

=6/6

=1

Mid point=(x1+x2/2 , y1+y2/2)

=(-3+3/2 , -5+1/2)

=(0/2 , -4/2)

=(0 , -2)

Now, (0,-2)=(x1,y1)

Equation:

y-y1=m(x-x1)

y+2=1(x-0)

y+2=1x

y+2-x=0 is the required equation.

where does the z at is it on the x axes or on the y axes any way if it is on the y axes put it horizontally and if it is on the x axes put it vertically