If a system including the quadratic equation representing the parabola and a linear equation has no solution, which linear equation could be the second equation in the system?
OA y = 6
OB. y = 25 + 6
OC 25 - y = 0
OD. ks = y +4

i did it myself and i got 4.2 (b) hope its right

step-by-step explanation:

more detail

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)