The area A of a sector of a circle is given by A= πr^2 S/ 360, where r is the radius of the circle and S is the angle measure (in degrees) of the sector. Solve the equation for S to find the angle measure given the radius and area of the circle. A) S = Aπr^2 / 360B) S = πr^2 / 360AC) S = 360A / πr^2D) S = 360πr^2 / A

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

cant open file sorry!

step-by-step explanation:

9x

i believe that the answer is

b. y-1=-2(x-4)

hope this !