Mathematics, 03.10.2021 14:40 phaalexander

WILL MARK BRAINLIEST

Answers: 2

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Answer from: isabel2007riverton

x = 20

Step-by-step explanation:

50 - 38 = 12

a^2 + b^2 = c^2

16^2 + 12^2 = x^2

256 + 144 = x^2

400 = x^2

x = $\sqrt{400}$

x = 20

Answer from: InchantingCrazy2168

$\huge\mathfrak{\underline{}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\large\bf{=20 }$

__________________________________________

$\large\bf{\underline{Given:}}$

A trapezium ABDE with sides 38 , 16 , 50 and x

$\large\bf{\underline{To\: find :}}$

The value of x

$\large\bf{\underline{Construction:}}$

Join C to E || AB

$\setlength{\unitlength}{0.8cm}\begin{picture}(6,5)\linethickness{.4mm}\put(1,1){\line(1,0){4.5}}\put(1,1){\line(0,1){3.5}}\qbezier(1,4.5)(1,4.5)(5.5,1)\put(.3,2.5){\large\bf 12}\put(2.8,.3){\large\bf 16}\put(1.02,1.02){\framebox(0.3,0.3)}\put(.7,4.8){\large\bf D}\put(.8,.3){\large\bf C}\put(5.8,.3){\large\bf E}\qbezier(4.5,1)(4.3,1.25)(4.6,1.7)\put(3.8,1.3){\large\bf $\Theta$}\end{picture}$

$\setlength{\unitlength}{0.75cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 16 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 38 cm}\put(-0.5,-0.4){\bf B}\put(-0.5,3.2){\bf C}\put(5.3,-0.4){\bf A}\put(5.3,3.2){\bf E}\end{picture}$

$\large\bf{\underline{Hence,}}$

CD = BD-BC

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎⟹CD = 50 - 38

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎⟹CD = 12

$\large\bf{Since,}$

AB || CE And ABDE is a trapezium , Therefore ABCE is a rectangle

$\large\bf{\underline{Therefore}}$

AB = CE

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎⟹ CE = 16

$\large\bf{\underline{In\: triangle\:DCE}}$

${\large\bf{Using\: Pythagoras\: theorem:}$

$\boxed{\large\bf\pink{DE^2 = CD^2 + CE^2}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\large\bf{⟹x^2 = 12^2 + 16^2}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\large\bf{⟹x^2 = 144 + 256}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\large\bf{⟹x^2 = 400}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\large \bf \:⟹ {x} = \sqrt{400}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\boxed{\large\bf{⟹x= 20}}$

Answer from: Quest

ℓσℓ ιт ∂σит тяσυвℓє мє αт αℓℓ ιм gℓα∂ тσ нєℓρ ρρℓ συт

ωє ιт ¢αи вє ωяιттєи αѕ

тнє єχα¢т fσям: 89/9тнє ∂є¢ιмαℓ fσям: 9.ιт яєαρєαтѕ)αи∂ тнє мιχє∂ иυмвєя fσям 9 8/9

step-by-step explanation:

нσρє ι ¢συℓ∂ нєℓρ уσυ συт

Answer from: Quest

the circumference of a circle is, 10.676 cm.

step-by-step explanation:

the formula for circumference of a circle is given by:

$c = \pi d$

where

c is the circumference of a circle and

d is the diameter of a circle.

given: diameter(d) = 3.4 cm and use $\pi = 3.14$

substitute these values in [1] we get;

$c = 3.14 \times 3.4 = 10.76$ cm

therefore, the circumference of a circle is, 10.676 cm

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