The sum of the present ages of a father and his son is 40 years.4years hence father will be three times as old as his son will be. Find their present ages

Father 32, son 8

Step-by-step explanation:

A+B =40

(A+4)/3 = B+4

40 + 4 + 4 = 48 years (present sum of ages of father and son)

Father : Son : Sum

   3      :   1    :    4

4 units = 48 years    

  1 unit = 48 years ÷ 4

            = 12 years

Father's present age = 3 × 12 years - 4 years

                                   = 36 - 4

                                   = 32 years

Son's present age = 12 years - 4 years

                              = 8 years

his chances of getting a coin of higher value is 4/19

step-by-step explanation: